1 solutions

  • 0
    @ 2025-1-22 12:12:51

    C++ :

    #include <iostream>
    using namespace std;
    
    int main() {
        int N;
        cin >> N;  // 读取输入
    
        // 计算偶数和奇数的个数
        int even_count = N / 2;
        int odd_count = (N + 1) / 2;
    
        // 计算数对数量
        int result = even_count * odd_count;
    
        // 输出结果
        cout << result << endl;
    
        return 0;
    }
    
    • 1

    Information

    ID
    703
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    1
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