1 solutions

  • 0
    @ 2025-1-22 12:12:50

    C++ :

    #include <iostream>
    #include <algorithm>  // 用于 min 函数
    
    using namespace std;
    
    int main() {
        int A, B, C;
        cin >> A >> B >> C;
    
        // 计算最多可以买多少个糖瓜
        int max_possible = B / A;
    
        // 取 min(max_possible, C) 作为最终结果
        int result = min(max_possible, C);
    
        cout << result << endl;
    
        return 0;
    }
    
    • 1

    Information

    ID
    696
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    1
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